3.1037 \(\int (a+b x)^3 (A+B x) (d+e x)^3 \, dx\)

Optimal. Leaf size=159 \[ \frac {e^2 (a+b x)^7 (-4 a B e+A b e+3 b B d)}{7 b^5}+\frac {e (a+b x)^6 (b d-a e) (-2 a B e+A b e+b B d)}{2 b^5}+\frac {(a+b x)^5 (b d-a e)^2 (-4 a B e+3 A b e+b B d)}{5 b^5}+\frac {(a+b x)^4 (A b-a B) (b d-a e)^3}{4 b^5}+\frac {B e^3 (a+b x)^8}{8 b^5} \]

[Out]

1/4*(A*b-B*a)*(-a*e+b*d)^3*(b*x+a)^4/b^5+1/5*(-a*e+b*d)^2*(3*A*b*e-4*B*a*e+B*b*d)*(b*x+a)^5/b^5+1/2*e*(-a*e+b*
d)*(A*b*e-2*B*a*e+B*b*d)*(b*x+a)^6/b^5+1/7*e^2*(A*b*e-4*B*a*e+3*B*b*d)*(b*x+a)^7/b^5+1/8*B*e^3*(b*x+a)^8/b^5

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Rubi [A]  time = 0.25, antiderivative size = 159, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {77} \[ \frac {e^2 (a+b x)^7 (-4 a B e+A b e+3 b B d)}{7 b^5}+\frac {e (a+b x)^6 (b d-a e) (-2 a B e+A b e+b B d)}{2 b^5}+\frac {(a+b x)^5 (b d-a e)^2 (-4 a B e+3 A b e+b B d)}{5 b^5}+\frac {(a+b x)^4 (A b-a B) (b d-a e)^3}{4 b^5}+\frac {B e^3 (a+b x)^8}{8 b^5} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x)^3*(A + B*x)*(d + e*x)^3,x]

[Out]

((A*b - a*B)*(b*d - a*e)^3*(a + b*x)^4)/(4*b^5) + ((b*d - a*e)^2*(b*B*d + 3*A*b*e - 4*a*B*e)*(a + b*x)^5)/(5*b
^5) + (e*(b*d - a*e)*(b*B*d + A*b*e - 2*a*B*e)*(a + b*x)^6)/(2*b^5) + (e^2*(3*b*B*d + A*b*e - 4*a*B*e)*(a + b*
x)^7)/(7*b^5) + (B*e^3*(a + b*x)^8)/(8*b^5)

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin {align*} \int (a+b x)^3 (A+B x) (d+e x)^3 \, dx &=\int \left (\frac {(A b-a B) (b d-a e)^3 (a+b x)^3}{b^4}+\frac {(b d-a e)^2 (b B d+3 A b e-4 a B e) (a+b x)^4}{b^4}+\frac {3 e (b d-a e) (b B d+A b e-2 a B e) (a+b x)^5}{b^4}+\frac {e^2 (3 b B d+A b e-4 a B e) (a+b x)^6}{b^4}+\frac {B e^3 (a+b x)^7}{b^4}\right ) \, dx\\ &=\frac {(A b-a B) (b d-a e)^3 (a+b x)^4}{4 b^5}+\frac {(b d-a e)^2 (b B d+3 A b e-4 a B e) (a+b x)^5}{5 b^5}+\frac {e (b d-a e) (b B d+A b e-2 a B e) (a+b x)^6}{2 b^5}+\frac {e^2 (3 b B d+A b e-4 a B e) (a+b x)^7}{7 b^5}+\frac {B e^3 (a+b x)^8}{8 b^5}\\ \end {align*}

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Mathematica [A]  time = 0.11, size = 297, normalized size = 1.87 \[ a^3 A d^3 x+a d x^3 \left (A \left (a^2 e^2+3 a b d e+b^2 d^2\right )+a B d (a e+b d)\right )+\frac {1}{2} b e x^6 \left (a^2 B e^2+a b e (A e+3 B d)+b^2 d (A e+B d)\right )+\frac {1}{2} a^2 d^2 x^2 (3 A (a e+b d)+a B d)+\frac {1}{5} x^5 \left (a^3 B e^3+3 a^2 b e^2 (A e+3 B d)+9 a b^2 d e (A e+B d)+b^3 d^2 (3 A e+B d)\right )+\frac {1}{4} x^4 \left (3 a B d \left (a^2 e^2+3 a b d e+b^2 d^2\right )+A \left (a^3 e^3+9 a^2 b d e^2+9 a b^2 d^2 e+b^3 d^3\right )\right )+\frac {1}{7} b^2 e^2 x^7 (3 a B e+A b e+3 b B d)+\frac {1}{8} b^3 B e^3 x^8 \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x)^3*(A + B*x)*(d + e*x)^3,x]

[Out]

a^3*A*d^3*x + (a^2*d^2*(a*B*d + 3*A*(b*d + a*e))*x^2)/2 + a*d*(a*B*d*(b*d + a*e) + A*(b^2*d^2 + 3*a*b*d*e + a^
2*e^2))*x^3 + ((3*a*B*d*(b^2*d^2 + 3*a*b*d*e + a^2*e^2) + A*(b^3*d^3 + 9*a*b^2*d^2*e + 9*a^2*b*d*e^2 + a^3*e^3
))*x^4)/4 + ((a^3*B*e^3 + 9*a*b^2*d*e*(B*d + A*e) + 3*a^2*b*e^2*(3*B*d + A*e) + b^3*d^2*(B*d + 3*A*e))*x^5)/5
+ (b*e*(a^2*B*e^2 + b^2*d*(B*d + A*e) + a*b*e*(3*B*d + A*e))*x^6)/2 + (b^2*e^2*(3*b*B*d + A*b*e + 3*a*B*e)*x^7
)/7 + (b^3*B*e^3*x^8)/8

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fricas [B]  time = 0.82, size = 410, normalized size = 2.58 \[ \frac {1}{8} x^{8} e^{3} b^{3} B + \frac {3}{7} x^{7} e^{2} d b^{3} B + \frac {3}{7} x^{7} e^{3} b^{2} a B + \frac {1}{7} x^{7} e^{3} b^{3} A + \frac {1}{2} x^{6} e d^{2} b^{3} B + \frac {3}{2} x^{6} e^{2} d b^{2} a B + \frac {1}{2} x^{6} e^{3} b a^{2} B + \frac {1}{2} x^{6} e^{2} d b^{3} A + \frac {1}{2} x^{6} e^{3} b^{2} a A + \frac {1}{5} x^{5} d^{3} b^{3} B + \frac {9}{5} x^{5} e d^{2} b^{2} a B + \frac {9}{5} x^{5} e^{2} d b a^{2} B + \frac {1}{5} x^{5} e^{3} a^{3} B + \frac {3}{5} x^{5} e d^{2} b^{3} A + \frac {9}{5} x^{5} e^{2} d b^{2} a A + \frac {3}{5} x^{5} e^{3} b a^{2} A + \frac {3}{4} x^{4} d^{3} b^{2} a B + \frac {9}{4} x^{4} e d^{2} b a^{2} B + \frac {3}{4} x^{4} e^{2} d a^{3} B + \frac {1}{4} x^{4} d^{3} b^{3} A + \frac {9}{4} x^{4} e d^{2} b^{2} a A + \frac {9}{4} x^{4} e^{2} d b a^{2} A + \frac {1}{4} x^{4} e^{3} a^{3} A + x^{3} d^{3} b a^{2} B + x^{3} e d^{2} a^{3} B + x^{3} d^{3} b^{2} a A + 3 x^{3} e d^{2} b a^{2} A + x^{3} e^{2} d a^{3} A + \frac {1}{2} x^{2} d^{3} a^{3} B + \frac {3}{2} x^{2} d^{3} b a^{2} A + \frac {3}{2} x^{2} e d^{2} a^{3} A + x d^{3} a^{3} A \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^3*(B*x+A)*(e*x+d)^3,x, algorithm="fricas")

[Out]

1/8*x^8*e^3*b^3*B + 3/7*x^7*e^2*d*b^3*B + 3/7*x^7*e^3*b^2*a*B + 1/7*x^7*e^3*b^3*A + 1/2*x^6*e*d^2*b^3*B + 3/2*
x^6*e^2*d*b^2*a*B + 1/2*x^6*e^3*b*a^2*B + 1/2*x^6*e^2*d*b^3*A + 1/2*x^6*e^3*b^2*a*A + 1/5*x^5*d^3*b^3*B + 9/5*
x^5*e*d^2*b^2*a*B + 9/5*x^5*e^2*d*b*a^2*B + 1/5*x^5*e^3*a^3*B + 3/5*x^5*e*d^2*b^3*A + 9/5*x^5*e^2*d*b^2*a*A +
3/5*x^5*e^3*b*a^2*A + 3/4*x^4*d^3*b^2*a*B + 9/4*x^4*e*d^2*b*a^2*B + 3/4*x^4*e^2*d*a^3*B + 1/4*x^4*d^3*b^3*A +
9/4*x^4*e*d^2*b^2*a*A + 9/4*x^4*e^2*d*b*a^2*A + 1/4*x^4*e^3*a^3*A + x^3*d^3*b*a^2*B + x^3*e*d^2*a^3*B + x^3*d^
3*b^2*a*A + 3*x^3*e*d^2*b*a^2*A + x^3*e^2*d*a^3*A + 1/2*x^2*d^3*a^3*B + 3/2*x^2*d^3*b*a^2*A + 3/2*x^2*e*d^2*a^
3*A + x*d^3*a^3*A

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giac [B]  time = 1.16, size = 402, normalized size = 2.53 \[ \frac {1}{8} \, B b^{3} x^{8} e^{3} + \frac {3}{7} \, B b^{3} d x^{7} e^{2} + \frac {1}{2} \, B b^{3} d^{2} x^{6} e + \frac {1}{5} \, B b^{3} d^{3} x^{5} + \frac {3}{7} \, B a b^{2} x^{7} e^{3} + \frac {1}{7} \, A b^{3} x^{7} e^{3} + \frac {3}{2} \, B a b^{2} d x^{6} e^{2} + \frac {1}{2} \, A b^{3} d x^{6} e^{2} + \frac {9}{5} \, B a b^{2} d^{2} x^{5} e + \frac {3}{5} \, A b^{3} d^{2} x^{5} e + \frac {3}{4} \, B a b^{2} d^{3} x^{4} + \frac {1}{4} \, A b^{3} d^{3} x^{4} + \frac {1}{2} \, B a^{2} b x^{6} e^{3} + \frac {1}{2} \, A a b^{2} x^{6} e^{3} + \frac {9}{5} \, B a^{2} b d x^{5} e^{2} + \frac {9}{5} \, A a b^{2} d x^{5} e^{2} + \frac {9}{4} \, B a^{2} b d^{2} x^{4} e + \frac {9}{4} \, A a b^{2} d^{2} x^{4} e + B a^{2} b d^{3} x^{3} + A a b^{2} d^{3} x^{3} + \frac {1}{5} \, B a^{3} x^{5} e^{3} + \frac {3}{5} \, A a^{2} b x^{5} e^{3} + \frac {3}{4} \, B a^{3} d x^{4} e^{2} + \frac {9}{4} \, A a^{2} b d x^{4} e^{2} + B a^{3} d^{2} x^{3} e + 3 \, A a^{2} b d^{2} x^{3} e + \frac {1}{2} \, B a^{3} d^{3} x^{2} + \frac {3}{2} \, A a^{2} b d^{3} x^{2} + \frac {1}{4} \, A a^{3} x^{4} e^{3} + A a^{3} d x^{3} e^{2} + \frac {3}{2} \, A a^{3} d^{2} x^{2} e + A a^{3} d^{3} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^3*(B*x+A)*(e*x+d)^3,x, algorithm="giac")

[Out]

1/8*B*b^3*x^8*e^3 + 3/7*B*b^3*d*x^7*e^2 + 1/2*B*b^3*d^2*x^6*e + 1/5*B*b^3*d^3*x^5 + 3/7*B*a*b^2*x^7*e^3 + 1/7*
A*b^3*x^7*e^3 + 3/2*B*a*b^2*d*x^6*e^2 + 1/2*A*b^3*d*x^6*e^2 + 9/5*B*a*b^2*d^2*x^5*e + 3/5*A*b^3*d^2*x^5*e + 3/
4*B*a*b^2*d^3*x^4 + 1/4*A*b^3*d^3*x^4 + 1/2*B*a^2*b*x^6*e^3 + 1/2*A*a*b^2*x^6*e^3 + 9/5*B*a^2*b*d*x^5*e^2 + 9/
5*A*a*b^2*d*x^5*e^2 + 9/4*B*a^2*b*d^2*x^4*e + 9/4*A*a*b^2*d^2*x^4*e + B*a^2*b*d^3*x^3 + A*a*b^2*d^3*x^3 + 1/5*
B*a^3*x^5*e^3 + 3/5*A*a^2*b*x^5*e^3 + 3/4*B*a^3*d*x^4*e^2 + 9/4*A*a^2*b*d*x^4*e^2 + B*a^3*d^2*x^3*e + 3*A*a^2*
b*d^2*x^3*e + 1/2*B*a^3*d^3*x^2 + 3/2*A*a^2*b*d^3*x^2 + 1/4*A*a^3*x^4*e^3 + A*a^3*d*x^3*e^2 + 3/2*A*a^3*d^2*x^
2*e + A*a^3*d^3*x

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maple [B]  time = 0.00, size = 339, normalized size = 2.13 \[ \frac {B \,b^{3} e^{3} x^{8}}{8}+A \,a^{3} d^{3} x +\frac {\left (3 B \,b^{3} d \,e^{2}+\left (b^{3} A +3 a \,b^{2} B \right ) e^{3}\right ) x^{7}}{7}+\frac {\left (3 B \,b^{3} d^{2} e +3 \left (b^{3} A +3 a \,b^{2} B \right ) d \,e^{2}+\left (3 a \,b^{2} A +3 a^{2} b B \right ) e^{3}\right ) x^{6}}{6}+\frac {\left (B \,b^{3} d^{3}+3 \left (b^{3} A +3 a \,b^{2} B \right ) d^{2} e +3 \left (3 a \,b^{2} A +3 a^{2} b B \right ) d \,e^{2}+\left (3 A \,a^{2} b +B \,a^{3}\right ) e^{3}\right ) x^{5}}{5}+\frac {\left (A \,a^{3} e^{3}+\left (b^{3} A +3 a \,b^{2} B \right ) d^{3}+3 \left (3 a \,b^{2} A +3 a^{2} b B \right ) d^{2} e +3 \left (3 A \,a^{2} b +B \,a^{3}\right ) d \,e^{2}\right ) x^{4}}{4}+\frac {\left (3 A \,a^{3} d \,e^{2}+\left (3 a \,b^{2} A +3 a^{2} b B \right ) d^{3}+3 \left (3 A \,a^{2} b +B \,a^{3}\right ) d^{2} e \right ) x^{3}}{3}+\frac {\left (3 A \,a^{3} d^{2} e +\left (3 A \,a^{2} b +B \,a^{3}\right ) d^{3}\right ) x^{2}}{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x+a)^3*(B*x+A)*(e*x+d)^3,x)

[Out]

1/8*b^3*B*e^3*x^8+1/7*((A*b^3+3*B*a*b^2)*e^3+3*b^3*B*d*e^2)*x^7+1/6*((3*A*a*b^2+3*B*a^2*b)*e^3+3*(A*b^3+3*B*a*
b^2)*d*e^2+3*b^3*B*d^2*e)*x^6+1/5*((3*A*a^2*b+B*a^3)*e^3+3*(3*A*a*b^2+3*B*a^2*b)*d*e^2+3*(A*b^3+3*B*a*b^2)*d^2
*e+b^3*B*d^3)*x^5+1/4*(a^3*A*e^3+3*(3*A*a^2*b+B*a^3)*d*e^2+3*(3*A*a*b^2+3*B*a^2*b)*d^2*e+(A*b^3+3*B*a*b^2)*d^3
)*x^4+1/3*(3*a^3*A*d*e^2+3*(3*A*a^2*b+B*a^3)*d^2*e+(3*A*a*b^2+3*B*a^2*b)*d^3)*x^3+1/2*(3*a^3*A*d^2*e+(3*A*a^2*
b+B*a^3)*d^3)*x^2+a^3*A*d^3*x

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maxima [B]  time = 0.52, size = 325, normalized size = 2.04 \[ \frac {1}{8} \, B b^{3} e^{3} x^{8} + A a^{3} d^{3} x + \frac {1}{7} \, {\left (3 \, B b^{3} d e^{2} + {\left (3 \, B a b^{2} + A b^{3}\right )} e^{3}\right )} x^{7} + \frac {1}{2} \, {\left (B b^{3} d^{2} e + {\left (3 \, B a b^{2} + A b^{3}\right )} d e^{2} + {\left (B a^{2} b + A a b^{2}\right )} e^{3}\right )} x^{6} + \frac {1}{5} \, {\left (B b^{3} d^{3} + 3 \, {\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e + 9 \, {\left (B a^{2} b + A a b^{2}\right )} d e^{2} + {\left (B a^{3} + 3 \, A a^{2} b\right )} e^{3}\right )} x^{5} + \frac {1}{4} \, {\left (A a^{3} e^{3} + {\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} + 9 \, {\left (B a^{2} b + A a b^{2}\right )} d^{2} e + 3 \, {\left (B a^{3} + 3 \, A a^{2} b\right )} d e^{2}\right )} x^{4} + {\left (A a^{3} d e^{2} + {\left (B a^{2} b + A a b^{2}\right )} d^{3} + {\left (B a^{3} + 3 \, A a^{2} b\right )} d^{2} e\right )} x^{3} + \frac {1}{2} \, {\left (3 \, A a^{3} d^{2} e + {\left (B a^{3} + 3 \, A a^{2} b\right )} d^{3}\right )} x^{2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)^3*(B*x+A)*(e*x+d)^3,x, algorithm="maxima")

[Out]

1/8*B*b^3*e^3*x^8 + A*a^3*d^3*x + 1/7*(3*B*b^3*d*e^2 + (3*B*a*b^2 + A*b^3)*e^3)*x^7 + 1/2*(B*b^3*d^2*e + (3*B*
a*b^2 + A*b^3)*d*e^2 + (B*a^2*b + A*a*b^2)*e^3)*x^6 + 1/5*(B*b^3*d^3 + 3*(3*B*a*b^2 + A*b^3)*d^2*e + 9*(B*a^2*
b + A*a*b^2)*d*e^2 + (B*a^3 + 3*A*a^2*b)*e^3)*x^5 + 1/4*(A*a^3*e^3 + (3*B*a*b^2 + A*b^3)*d^3 + 9*(B*a^2*b + A*
a*b^2)*d^2*e + 3*(B*a^3 + 3*A*a^2*b)*d*e^2)*x^4 + (A*a^3*d*e^2 + (B*a^2*b + A*a*b^2)*d^3 + (B*a^3 + 3*A*a^2*b)
*d^2*e)*x^3 + 1/2*(3*A*a^3*d^2*e + (B*a^3 + 3*A*a^2*b)*d^3)*x^2

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mupad [B]  time = 0.10, size = 334, normalized size = 2.10 \[ x^3\,\left (B\,a^3\,d^2\,e+A\,a^3\,d\,e^2+B\,a^2\,b\,d^3+3\,A\,a^2\,b\,d^2\,e+A\,a\,b^2\,d^3\right )+x^6\,\left (\frac {B\,a^2\,b\,e^3}{2}+\frac {3\,B\,a\,b^2\,d\,e^2}{2}+\frac {A\,a\,b^2\,e^3}{2}+\frac {B\,b^3\,d^2\,e}{2}+\frac {A\,b^3\,d\,e^2}{2}\right )+x^4\,\left (\frac {3\,B\,a^3\,d\,e^2}{4}+\frac {A\,a^3\,e^3}{4}+\frac {9\,B\,a^2\,b\,d^2\,e}{4}+\frac {9\,A\,a^2\,b\,d\,e^2}{4}+\frac {3\,B\,a\,b^2\,d^3}{4}+\frac {9\,A\,a\,b^2\,d^2\,e}{4}+\frac {A\,b^3\,d^3}{4}\right )+x^5\,\left (\frac {B\,a^3\,e^3}{5}+\frac {9\,B\,a^2\,b\,d\,e^2}{5}+\frac {3\,A\,a^2\,b\,e^3}{5}+\frac {9\,B\,a\,b^2\,d^2\,e}{5}+\frac {9\,A\,a\,b^2\,d\,e^2}{5}+\frac {B\,b^3\,d^3}{5}+\frac {3\,A\,b^3\,d^2\,e}{5}\right )+\frac {a^2\,d^2\,x^2\,\left (3\,A\,a\,e+3\,A\,b\,d+B\,a\,d\right )}{2}+\frac {b^2\,e^2\,x^7\,\left (A\,b\,e+3\,B\,a\,e+3\,B\,b\,d\right )}{7}+A\,a^3\,d^3\,x+\frac {B\,b^3\,e^3\,x^8}{8} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((A + B*x)*(a + b*x)^3*(d + e*x)^3,x)

[Out]

x^3*(A*a*b^2*d^3 + B*a^2*b*d^3 + A*a^3*d*e^2 + B*a^3*d^2*e + 3*A*a^2*b*d^2*e) + x^6*((A*a*b^2*e^3)/2 + (B*a^2*
b*e^3)/2 + (A*b^3*d*e^2)/2 + (B*b^3*d^2*e)/2 + (3*B*a*b^2*d*e^2)/2) + x^4*((A*a^3*e^3)/4 + (A*b^3*d^3)/4 + (3*
B*a*b^2*d^3)/4 + (3*B*a^3*d*e^2)/4 + (9*A*a*b^2*d^2*e)/4 + (9*A*a^2*b*d*e^2)/4 + (9*B*a^2*b*d^2*e)/4) + x^5*((
B*a^3*e^3)/5 + (B*b^3*d^3)/5 + (3*A*a^2*b*e^3)/5 + (3*A*b^3*d^2*e)/5 + (9*A*a*b^2*d*e^2)/5 + (9*B*a*b^2*d^2*e)
/5 + (9*B*a^2*b*d*e^2)/5) + (a^2*d^2*x^2*(3*A*a*e + 3*A*b*d + B*a*d))/2 + (b^2*e^2*x^7*(A*b*e + 3*B*a*e + 3*B*
b*d))/7 + A*a^3*d^3*x + (B*b^3*e^3*x^8)/8

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sympy [B]  time = 0.13, size = 422, normalized size = 2.65 \[ A a^{3} d^{3} x + \frac {B b^{3} e^{3} x^{8}}{8} + x^{7} \left (\frac {A b^{3} e^{3}}{7} + \frac {3 B a b^{2} e^{3}}{7} + \frac {3 B b^{3} d e^{2}}{7}\right ) + x^{6} \left (\frac {A a b^{2} e^{3}}{2} + \frac {A b^{3} d e^{2}}{2} + \frac {B a^{2} b e^{3}}{2} + \frac {3 B a b^{2} d e^{2}}{2} + \frac {B b^{3} d^{2} e}{2}\right ) + x^{5} \left (\frac {3 A a^{2} b e^{3}}{5} + \frac {9 A a b^{2} d e^{2}}{5} + \frac {3 A b^{3} d^{2} e}{5} + \frac {B a^{3} e^{3}}{5} + \frac {9 B a^{2} b d e^{2}}{5} + \frac {9 B a b^{2} d^{2} e}{5} + \frac {B b^{3} d^{3}}{5}\right ) + x^{4} \left (\frac {A a^{3} e^{3}}{4} + \frac {9 A a^{2} b d e^{2}}{4} + \frac {9 A a b^{2} d^{2} e}{4} + \frac {A b^{3} d^{3}}{4} + \frac {3 B a^{3} d e^{2}}{4} + \frac {9 B a^{2} b d^{2} e}{4} + \frac {3 B a b^{2} d^{3}}{4}\right ) + x^{3} \left (A a^{3} d e^{2} + 3 A a^{2} b d^{2} e + A a b^{2} d^{3} + B a^{3} d^{2} e + B a^{2} b d^{3}\right ) + x^{2} \left (\frac {3 A a^{3} d^{2} e}{2} + \frac {3 A a^{2} b d^{3}}{2} + \frac {B a^{3} d^{3}}{2}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x+a)**3*(B*x+A)*(e*x+d)**3,x)

[Out]

A*a**3*d**3*x + B*b**3*e**3*x**8/8 + x**7*(A*b**3*e**3/7 + 3*B*a*b**2*e**3/7 + 3*B*b**3*d*e**2/7) + x**6*(A*a*
b**2*e**3/2 + A*b**3*d*e**2/2 + B*a**2*b*e**3/2 + 3*B*a*b**2*d*e**2/2 + B*b**3*d**2*e/2) + x**5*(3*A*a**2*b*e*
*3/5 + 9*A*a*b**2*d*e**2/5 + 3*A*b**3*d**2*e/5 + B*a**3*e**3/5 + 9*B*a**2*b*d*e**2/5 + 9*B*a*b**2*d**2*e/5 + B
*b**3*d**3/5) + x**4*(A*a**3*e**3/4 + 9*A*a**2*b*d*e**2/4 + 9*A*a*b**2*d**2*e/4 + A*b**3*d**3/4 + 3*B*a**3*d*e
**2/4 + 9*B*a**2*b*d**2*e/4 + 3*B*a*b**2*d**3/4) + x**3*(A*a**3*d*e**2 + 3*A*a**2*b*d**2*e + A*a*b**2*d**3 + B
*a**3*d**2*e + B*a**2*b*d**3) + x**2*(3*A*a**3*d**2*e/2 + 3*A*a**2*b*d**3/2 + B*a**3*d**3/2)

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